A chord of a radius 12 cm subtends an angle of 120° at the centre. Find the area of the
corresponding segment of the circle. (Use r = 3.14 and 3 = 1.73)
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Use the formula
(Pie)r^2(theta)/360-
(r^2)(sin(theta)/2)(cos(theta)/2)
Where
Pie=3.14
R=12
Theta=120 degree
(Pie)r^2(theta)/360-
(r^2)(sin(theta)/2)(cos(theta)/2)
Where
Pie=3.14
R=12
Theta=120 degree
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