Question

a chord of circle of radius 7 cm subtends a right angle at the centre find the area of major sector of the circle

Answer 1

Answer:

Step-by-step explanation:

Area of major secgment = 22/7 (7)7 (4_1/4)

=154 (3/4)

=115.5cm2

The major segment =115.5cm2

Answer 2

Given:

A chord of a circle of radius 7 cm subtends a right angle at the centre

To Find:

Find the area of the major sector of the circle

Solution:

It is given that the chord of a circle of radius 7cm subtends a right angle at the centre and we need to find the area of the major sector.

The formula for the area of the sector is,

$A=\pi r^2\frac{\theta}{360}$

So because it is a minor sector at 90 degrees and for the major sector the angle will be (360-90)=270 degrees, now using this value to find the value of the major sector of the circle,

$A=\pi r^2\frac{\theta}{360} \\=\frac{22}{7}*7*7*\frac{270}{360} \\=115.5cm^2$

Hence, the area of the major sector of the circle is 115.5sq.cm.