Question

a chord of lengtg 24cm of a circle is at a distance of 5cm fron the centre. find the radius (with steps)
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Answer 1

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Look at the figure given below:-

In a circle AB is a chord of 24 cm, its distance from centre O is 5cm. We have to find the radius AO.

Applying pythagoras theorem:-

H²= p²+b²

AO²=CO²+AC²

AO²=(5)²+(12)²

AO²=25+144

AO²=169

$\sf \: AO = \sqrt{169} = 13$

So the length of radius is 13 cm

Hope it helps you.....

Answer 2

Answer:

In a circle AB is a chord of 24 cm, its distance from centre O is 5cm. We have to find the radius AO.

Applying pythagoras theorem:-

H²= p²+b²

AO²=CO²+AC²

AO²=(5)²+(12)²

AO²=25+144

AO²=169

\sf \: AO = \sqrt{169} = 13AO=

169

=13

So the length of radius is 13 cm