A chord of length 24 cm is at a distance of 5 cm from the centre of the circle. Find the length of the another chord of circle which is at a distance of 12 cm from the centre
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According to question and below figure OQ = 5cm,OP=12cm,
CD=24cm. And AO = CO (As a radius of the circle).
OQ ⊥ CD and intersecting CD at point O.
Therefore CQ = DQ = 12cm.
CO2 = CQ2 + QO2
CO2 = 122 + 52
By solving this CO = 13
therefore CO =AO = 13CM.
in triangle AOP,
AO2 = PO2 + AP2
AP2 = 132 - 122
By solving this AP = 5CM.
therefore AB = 10CM
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