Math, asked by 12381, 1 year ago

a chord of length 48 cm is drawn in a circle of radius 25 cm . calculate its distance from the center of the circle

Answers

Answered by Brenquoler
382

AB is the chord of the circle with centre O and radius OA

OM is perpendicular to AB

Therefore,

AB = 48 cm

OA = 25 cm

OM ⊥ AB

M is the mid-point of AB

AM = 1/2 AB = ½ × 48 = 24 cm

Now right ∆OAM,

OA2 = OM2 + AM2

(by Pythagoras Axiom)

(25)2 = OM² + (24)²

OM2 = (25)² – (24)² = 625 – 576

= 49 = (7)²

OM = 7 cm

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Answered by Anonymous
276

Step-by-step explanation:

\huge{\underline{\bold{\red{Question:⤵}}}}

A chord of length 48 cm is drawn in a circle of radius 25 cm . Calculate its distance from the center of the circle.

\huge\fbox\blue{Answer♡}

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⟼AB is the chord of the circle with centre O and radius OA

✰ OM is perpendicular to AB

⟼Therefore,

✰ AB = 48 cm

✰ OA = 25 cm

✰ OM ⊥ AB

⟼M is the mid-point of AB

✰ AM = 1/2 AB = ½ × 48 = 24 cm

⟼Now right ∆OAM,

✰ OA2 = OM2 + AM2

(by Pythagoras Axiom)

✰ (25)2 = OM² + (24)²

✰ OM2 = (25)² – (24)² = 625 – 576

= 49 = (7)²

⟼OM = 7 cm

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