Question

a chord of length of 6.2 cm is at a distance of 3.5 cm from the centre of the circle if there is another chord of length 6.2 CM in the same circle find the distance of the chord from its Centre justify your answer

Answer 1

YOUR ANSWER IS 3.5 CM

BECAUSE THE SAME LENGTH OF CHORDS ARE HAVE SAME DISTANCE FROM THE CENTRE OF THE SAME CIRCLE

Answer 2

Answer : 3.5 cm

Exaplantion :- A chord of length 6.2cm is at a distance of 3.5 cm from the centre of the circle as shown in figure.
we know, a line passing through centre perpendicular bisector on chord .
So, radius of circle = r
Here r, 3.1cm , 3.5cm are the sides of right angled triangle
So, according to Pythagoras theorem,
r² = 3.1² + 3.5²------(1)

Now, another chord of same length 6.2cm drawn in circle . Similarly a line passing through centre of circle bisects it perpendicularly .
now, Let distance between chord and centre of circle is d
so, d , r, and 3.1cm are the sides of right angle triangle
by Pythagoras theorem,
r² = d² + 3.1²
Now, put equation (1),
3.5² + 3.1² = 3.1² + d²
d² = 3.5²
d = 3.5

Hence, distance between chord and center of circle is 3.5cm