A chord pq of a circle of radius 10 cm makes a right angle at the centre of the circle. find the area of the major and the minor segments.
Answers
When we subtract area of right triangle from area of minor sector we get area of minor segment .
Here, Area of minor segment = area of minor sector - area of right triangle
=[(theta/360) * pi * r^2] - 1/2 * base * height
= [(90/360) * 3.14 * 10^2] - 1/2 * 10 * 10
= [(1/4) * 3.14 * 10^2] - 1/2 * 10 * 10
= 78.5 - 50
= 28.5 cm^2
When we subtract area of minor segment from area of circle we get area of major segment .
Also, area of major segment = area of circle - Area of minor segment
= pi * r^2 - 28.5
= 3.14 * 10 * 10 - 28.5
= 285.5 cm^2
Answer is attached. Please refer.
