Question

A chum chum sweet contains sugar syrup 25% of the volume. Find how much syrup would be found in 100 such chum chum each shaped like a cylinder with two hemispherical ends with l=4 and d=1.4cm respectively​

Answer 1

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Answer 2

Therefore the quantity of sugar syrup in 100 chum chum is=467.5 cm³            

Step-by-step explanation:

Given the each chum chum shaped like a cylinder with two hemispherical ends with length l= 4 cm and d=1.4 cm.

The middle portion of a chum chum shaped like a cylinder.

The radius of the sphere will be subtracted from the total length to get the actually length of the cylinder.

Then the length the length of the cylinder portion ={4-(2×1.4)] cm

                                                                                   =1.2 cm.

The radius of the cylinder = The radius of the sphere = 1.4 cm

Therefore the volume of the cylinder potion =$\pi r^2h$

                                                                          $=[\pi \times (1.4)^2\times 1.2]$ cm³  

And volume of two hemisphere is $=2\times (\frac{2}{3} \times \pi r^3)$

                                                        $=[\frac{4}{3} \pi (1.4)^3]$ cm³

Therefore the total volume of each chum chum is                                                        

$=[\frac{4}{3} \pi (1.4)^3+\pi \times (1.4)^2\times 1.2]]$   cm³

=18.89   cm³

Total volume of 100 chum chum is =(100×18.89) cm³  

                                                           =1869 cm³

Given that, a chum chum sweet contains sugar syrup 25% of the volume.

Therefore the quantity of sugar syrup in 100 chum chum is

$=(\frac{25}{100} \times 1869)$ cm³

=467.5 cm³