Question

a circketer can throw a ball to maximum horizontal distance of 160m.

Answer 1

First we make some assumptions not specified in your problem.

We assume the only force acting on the ball is the force of gravity; that is, there is no drag and such.

Second, we assume the man threw the ball at forty five degrees w. r. t the ground level for the maximum horizontal range.

Third, we assume the distance X = 160 m is measure from the release point to the impact point and both are at the same level.

Let R be the horizontal distance, V the initial velocity. g= 10m/ s^2

In which case we can use the ideal maximum range equation R = V^2/g; so that V^2 = gR = 10*160 = 1600m^2/s^2 and V = 40 m/s is the initial speed(u).

We know that v^2- u^2= 2gs where s is the maximum vertical distance.

Here v= 0 and g= -g

Therefore

- 1600= 2 *-10 *s or s= -1600/ -20= 80m.

Answer 2

Hello mate here is your answer.

A cricketer can throw a ball to maximum horizontal distance of 160m.calculate the maximumvertical height to which he can throw a ball.given g=10.

Hope it helps you