A circle has A(1,3) and B(4,5) as opposite ends of a diameter.Find the equation of the perpendicular diameter
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Diameter of a circle is AB. Let the center of circle be O.
A = (1, 3). B = (4, 5).
=> Slope of AB: (5-3)/(4-1) = 2/3
=> Midpoint of AB = O = (5/2, 4)
We need the equation of diameter COD ⊥ AOB.
=> Slope of COD : - 3/2
COD passes through O.
Equation of COD: y = - 3/2 x + c
O lies on COD: 5/2 = - 3/2 * 4 + c
c = 17/2
=> Answer: ⊥r diameter: y = -3/2 x + 17/2
or 2 y + 3 x - 17 = 0
A = (1, 3). B = (4, 5).
=> Slope of AB: (5-3)/(4-1) = 2/3
=> Midpoint of AB = O = (5/2, 4)
We need the equation of diameter COD ⊥ AOB.
=> Slope of COD : - 3/2
COD passes through O.
Equation of COD: y = - 3/2 x + c
O lies on COD: 5/2 = - 3/2 * 4 + c
c = 17/2
=> Answer: ⊥r diameter: y = -3/2 x + 17/2
or 2 y + 3 x - 17 = 0
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