Question

Name Quad.formed by (4,5),(7,6),(4,3)(1,2) plz solve on notebook and send

Answer 1

In ∆ ABC area = 1/2 *4(6-3)+7(3-5)+4(5-6) = 1/2 4(3)+7(-2)+4(-1). =1/2*12+(-14)+(-4) = 1/2*30 = 15 sq units area of∆ ABC = Area of ∆BCD =1/2*7(2-3)+1(3-6)+4(6-2). = 1/2*7 (-1)+1(-3)+4(4). = 1/2*(-7)+(-3)+(16). = 1/2*26 = 13 sq units =Now add both areas of ∆ ABC + ∆BCD = 15+13 =28 sq unit's