Question

A circle has a radius of \sqrt{131}
131
​
square root of, 131, end square root units and is centered at (0,-4.3)(0,−4.3)left parenthesis, 0, comma, minus, 4, point, 3, right parenthesis.
Write the equation of this circle.

Answer 1

The equation of a circle with radius r and center at (h,k) is,

$(x-h)^2+(y-k)^2=r^2$

Here, circle has a radius of √131 units and is centered at (0,-4.3),

That is, h = 0,k = -4.3 and r = √131 units.

Thus, the equation of the circle is,

$(x-0)^2+(y+4.3)^2=(\sqrt{131})^2$

$x^2+(y+4.3)^2=131$

Therefore, the equation of the circle would be $x^2+(y+4.3)^2=131$.