Math, asked by tanu080404, 6 months ago

A circle has radius 3 units and its centrer
lies on the line y = x -1. If it passes
through the point (7,3), its equation is
1) x² + y2 - 4x - 6y+4= 0
2) x² + y2 - 14x-12 y - 76 = 0
3) x² + y2 - 8x -6y +136=0
4) x2 + y2 - 8x - 6y +16 = 0

Answers

Answered by ankitraj63188

2

Answer:

2

Step-by-step explanation:

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