Question

A circle has radius equal to 3 units and its centre lies on the line y=x-1. Find the equation of
the circle if it passes through (7,3).
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Answer 1

Answer:

two circles are possible

Step-by-step explanation:

please find attached

Answer 2

Answer:

Let (h, k) be the centre of the circle.

Then k = h – 1. Therefore, the equation of the circle is given by (x – h)2 + [y – (h – 1)]2 = 9

Given that the circle passes through the point (7, 3) and hence we get ⇒ h = 4 or h = 7.

Therefore, the required equations of the circles are x2 + y2 – 8x – 6y + 16 = 0 or, x2 + y2 – 14x – 12y + 76 =0