Question

A circle in the xyxyx, yplane has the equation (x+92)^2+(y+54)^2=73(x+92) 2 +(y+54) 2 =73left parenthesis, x, plus, 92, right parenthesis, start superscript, 2, end superscript, plus, left parenthesis, y, plus, 54, right parenthesis, start superscript, 2, end superscript, equals, 73. What is the length of the diameter of the circle?

Answer 1

Answer:

the length of the diameter of the circle = 2√73

Step-by-step explanation:

A circle in the x, y plane has the equation (x+92)^2 +(y+54)^2 =73

The center-radius form of the circle equation is in the format (x – h)2 + (y – k)2 = r2, with the center being at the point (h, k) and the radius being "r"

(x+92)² +(y+54)² =73

=> ( x - (-92))² + (y - (-54))² = √73²

Center = ( -92 , -54)

Radius = √73

Diameter = 2 * Radius = 2√73

the length of the diameter of the circle = 2√73