Question

a circle is drawn with centre as origin and passes through the point A(4,3).does this point Q (0,6) lies inside or outside the circle?

Answer 1

IF O is the center of circle, then OA is raidus, = Sq. root 4^2 + 3^2 = Sq. rt 25
= 5.
Radius = 5 units.
OQ = 6 units. 
OQ>Radius.
Q lies outside the circle!!

Answer 2

Answer:

Q (0,6) lies outside the circle.

Step-by-step explanation:

The center of the circle is O(0,0). The circle passes through the point A(4,3).

Distance formula:

$d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

Radius of the circle is OA.

$OA=\sqrt{(0-4)^2+(0-3)^2}=5$

The radius of circle 5 units.

The distance of OB is

$OB=\sqrt{(0-0)^2+(0-6)^2}=6$

The distsnce of OB is 6 units which greater than the radius of the circle.

Therefore Q (0,6) lies outside the circle.