Math, asked by punithchowdary1247, 1 year ago

A circle is drawn with origin as centre and passes through 13/2,0

Answers

Answered by amitnrw
2

The point  (-6,5/2) does not lies in the interior of circle

Step-by-step explanation:

A circle drawn with origin as the centre passes through (13/2,0)

(x - h)² + (y - k)² = r²

h & k = 0 as center is at origin

=> x² + y² = r²

Passes through 13/2  , 0

=> (13/2)² + 0² = r²

=> r² = (13/2)²

=>  x² + y² =  (13/2)²

x² + y² < (13/2)²  lies inside circle

The point    x² + y² ≥ (13/2)² does not lies in the interior of circle

option given are:

a) (-3/4,1) b) (2,7/3) c) (5,-1/2) d) (-6,5/2)

-3/4,1 =>  x² + y² =  25/16  = (5/4)² < (13/2)²

(2,7/3) => x² + y² =  85/9   < (13/2)²

(5,-1/2)  => x² + y² =  101/4   < (13/2)²

(-6,5/2) => x² + y² =  169/4   = (13/2)²

hence (-6,5/2)  does not lies in the interior of circle

it lies on circle

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