Base of a right pyramid is a square of side 10 cm . if the height of the pyramid is 12 cm , then its total surface area is
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total surface area = area of two bases + lateral surface area
now,
area of base is a square so area of each base = 10*10 = 100 sq unit
there are two bases so total area of base = 200 sq unit
now
lateral surface area = perimeter of edges * height
= 4*10*12 = 480sq unit
total surface area = 200 + 480 = 680 sq unit
now,
area of base is a square so area of each base = 10*10 = 100 sq unit
there are two bases so total area of base = 200 sq unit
now
lateral surface area = perimeter of edges * height
= 4*10*12 = 480sq unit
total surface area = 200 + 480 = 680 sq unit
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0
Answer:
Step-by-step explanation:
total surface area = area of two bases + lateral surface area
now,
area of base is a square so area of each base = 10*10 = 100 sq unit
there are two bases so total area of base = 200 sq unit
now
lateral surface area = perimeter of edges * height
= 4*10*12 = 480sq unit
total surface area = 200 + 480 = 680 sq unit
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