A circle is inscribed in a ABC, with sides AC, AB and BC as 8 cm, 10 cm and 12 cm
respectively (see below figure). Find the length of BE and CF.
Attachments:
Answers
Answered by
5
Hi✌️✌️
Solution:
We know that tangents from an external point are equal in length.
Given :
AB = 12 cm
BC= 8 cm
AC = 10 cm
Now let us take A as external point,thus
AD = AF
let AD = AF = x cm
So, DB = 12-x = BE [tangent from external point B]
CE = 8-12+x = -4+x = CF [tangent from external point C]
Since perimeter of ∆ABC does not change so
12+8+10= x+x+12-x+12-x-4+x-4+x
30=2x+16
2x=30-16
2x=14
x = 7 cm
So, AD = AE = 7 cm
BD=BE = 12-7=5 cm
CE=CF= -4+7=3 cm
Hope it helps you.
Similar questions
Math,
5 months ago
Math,
5 months ago
Math,
5 months ago
Chemistry,
11 months ago
Business Studies,
1 year ago