A circle of 3 cms radius lies inside and touches all the four sides of a square.the area(in sq.cm)of the square is
Anonymous:
36cm²
thanks bro
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radius of the circle =3 cm.
diameter of the circle =2×radius
=(2×3) cm
=6 cm
diameter of the circle =diagonal of the square
diagonal of the square =6 cm
let the side of the square be a.
by Pythagoras theorem,
a²+a²=6²
2a²=36
a²=36/2
a²=18
a=root 18
area of the square =(side)²
=a²
=(root 18)²
=18 sq cm
diameter of the circle =2×radius
=(2×3) cm
=6 cm
diameter of the circle =diagonal of the square
diagonal of the square =6 cm
let the side of the square be a.
by Pythagoras theorem,
a²+a²=6²
2a²=36
a²=36/2
a²=18
a=root 18
area of the square =(side)²
=a²
=(root 18)²
=18 sq cm
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