Question

A circle of radius 3 cm is removed from a circular sheet of radius 5 cm find. the area of of the remaining sheet

Answer 1

area of sheet
$\pi {r}^{2}$
22/7 × 5^2
area = 550/7 m^2
now area of removed sheet
= 22/7 × 3× 3
198/7 m^2
area of remaining sheet
550/7 - 198/7
352 / 7 m^2 remaining

Answer 2

$area \: of \: circle = \pi {r}^{2}$
So initially the whole circular sheet area=
$\frac{22}{7} \times {5}^{2} = \frac{22}{7} \times 25 \\ = \frac{550}{7} = 78.57$
Now area removed=
$\frac{22}{7} \times {3}^{2} = \frac{22}{7} \times 9 \\ = \frac{198}{7} = 28.28$
So area left is the difference of these 2 areas

$so \: \frac{550}{7} - \frac{198}{7} \\ = \frac{352}{7} \\ = 50.2857$
m²
I HOPE IT HELPS ...!!!