A circle of radius x has an equilateral triangle in it of side 9cm.Find the radius ...???
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1
Circumcircle radius (R) = x cm
s=27/2
area =sqrt(1230.18)= 35.07 {area = Sqrt(s(s-a)(s-b)(s-c)}
abc/4(area) = R
R=x=729/4(35.07)= 5.19 cm approx
s=27/2
area =sqrt(1230.18)= 35.07 {area = Sqrt(s(s-a)(s-b)(s-c)}
abc/4(area) = R
R=x=729/4(35.07)= 5.19 cm approx
Answered by
0
So easy.. We know eqularteral traingle has angle of 60 so when radius is draw it bisect now angle is 30. here is figure solve it for x and you will get radius
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