Question

A circle passes through the points (-1, -1) and (3, 7). Which of the following cannot also be a point on the circle?

1.(0, 1)
2. (1, 1)
3. (1, 0)
4. (0, 0)

Answer 1

(0,0) (1,1) ,(1,0)these points are not touching in the graph but

it touches at (0,1)

Answer 2

Answer:

(0,1) should not be on circle.

Step-by-step explanation:

• The points through which circle passes are (-1,-1) and (3,7).
• Then when we draw a straight line joining these two points Then the points that satisfy the equation of the line must not be a point on the circle.
• Hence the equation of the line is
  $y=mx+c$
• Then to find the value of m it is given to us by
  $m = \frac{y_{2}-y_{1}}{x_{2}-x_{1}}$
  $m=\frac{4}{2} =2$
• Hence the equation becomes
  $y=2x+c$
• And putting the point (-1,-1) we get the value of c as
  $c=1$
• So equation becomes
  $y=2*x+1$
• So the point that satisfy this equation is (0,1) so it should not lie on circle.
  #SPJ3