a circle touches all the four sides of a quadrilateral ABCD whose three sides are A B 6 cmBC 7cm and CD 4 cm find AD
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HEY THERE ..!!
↓ HERE IS YOURS SOLUTION ↓
◆ Let P,Q,R,S be the points where the circle touches the quadrilateral .
◆ From a point out side of the circle the two tangents to the circle are equal.
AP = AS,BP = BQ ,CR =
CQ , and DR = DS
◆ Adding;
AP + BP + CR + DR = AS + BQ + CQ + DS+ AB + CD = AD + BC
=> 6 + 4 = AD + 7
=> AD = 3 cm
★SO, THE ANSWER IS 3 CM★
↓FOR ANY DOUBT YOU CAN COMMENT DOWN↓
HOPE IT HELPS
↓ HERE IS YOURS SOLUTION ↓
◆ Let P,Q,R,S be the points where the circle touches the quadrilateral .
◆ From a point out side of the circle the two tangents to the circle are equal.
AP = AS,BP = BQ ,CR =
CQ , and DR = DS
◆ Adding;
AP + BP + CR + DR = AS + BQ + CQ + DS+ AB + CD = AD + BC
=> 6 + 4 = AD + 7
=> AD = 3 cm
★SO, THE ANSWER IS 3 CM★
↓FOR ANY DOUBT YOU CAN COMMENT DOWN↓
HOPE IT HELPS
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