if tana=1 and sin B=1/√2,find the value of cos(a+b),whre a and are acute angle
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firstly take tan a =1
tan a=tan45
a=45
now take sinb=1/√2
sinb=sin45
b=45
cos(a+b)=cos(45+45)=cos90=0
tan a=tan45
a=45
now take sinb=1/√2
sinb=sin45
b=45
cos(a+b)=cos(45+45)=cos90=0
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