A circle touches side BC of ΔABC at P, and sides AB and AC produced at Q and R respectively.If l is the perimeter of ΔABC ,then
A)l = AQ B) l = 2AQ C) l = 2/3AQ D) l = 3/2AQ E)None of these
Answers
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Thelengthsofthetangents,fromapointtoacircle,
areequal.
Therefore AB = AP, BQ = BP, BP = CP
Perimeter = AC + AB + BC = 2(AB) + BP + PC = 2(AB) + 2(BQ) = 2(AQ) = 30 cm
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