Question

A circle with area 9pi has a sector with a central angle of 60 degrees. what is the area of the sector?

Answer 1

Answer:

Area

Step-by-step explanation:

Area of circle = π$r^{2}$ = 9π

                            $r^{2} = 9 = 3^{2} \\r = 3$

Area of minor sector = π *Ф* $\frac{r^{2} }{360}$  ( where ∅ = angle = 60)

                                    = $\frac{22}{7} *60 *\frac{3^{2}}{360}$

                                   =$\frac{22*60*9}{7*360}$

                                   = 4.714