A circle with area A1 is contained in the interior of a larger circle with area A1+A2 if the
radius of the larger circle is 3 and A1,A2 and A1 +A2 are in A.P then the radius of smaller
circle is ?
Answers
Answered by
4
Step-by-step explanation:
Area of small circle =A
1
Area of larger circle =A
1
+A
2
Given that
(A
1
,A
2
,A
1
+A
2
) form an AP
Common difference
d=A
2
−A
1
=A
2
+A
1
−A
2
A
2
−A
1
=A
1
A
2
=2A
1
(1)
Radius of larger circle =3 units
Area of larger circle =π(3)
2
=9π
A
1
+A
2
=9π
From (1)
2A
1
+A
1
=9π
3A
1
=9π
A
1
=3π
πr
2
=3π
r=
3
units
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