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A circle with centre P is inscribed in the triangle ABC side AB BC Ac touch the circle at point L M N Radius of the circle is r PROVE THAT triangle ABC = 1/ 2 ( AB+BC+ AC)r

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Answered by itzJitesh
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The sides AB, BC and CA of triangle ABC touch a circle with center O and radius r at P, Q and R respectively.Prove that AB+CQ=AC+BQ and Area(ABC)=1/2×r×(perimeter of ABC)

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