A circuit consist of three resistance 4 Ohm,6 Ohm and 12 Ohm connected in parallel across a supply of 44V. Find out the current in the circuit and current in each resistance.
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Answer:
Total Resistance of Circuit=1/4+1/6+1/12
=2ohm
According to formulae=V=IR
V=POTENTIAL DIFFERENCE
I=ELECTRIC CURRENT
R=RESISTANCE
V=IR
I=V/R
I=44/2
TOTAL CURRENT IN CIRCUIT=22 Ampere
Current in 1 resistance
I=V/R
I=44/4
CURRENT IN 1 RESISTANCE=11 Ampere
CURRENT IN 2 RESISTANCE
I=V/R
I=44/6
CURRENT IN 2 RESISTANCE=7.3 Ampere
CURRENT IN 3 RESISTANCE
I=V/R
I=44/12
CURRENT IN 3 RESISTANCE=3.6 Ampere
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