Question

A circuit consists of a resistor of l ohm in series
with a parallel arrangement of resistors of 6 ohm and
3 ohm. Calculate the total resistance of the circuit.
Draw a diagram of the arrangment. ​

Answer 1

Explanation:

I hope it'll be of help to you

Answer 2

Answer:

5 Ω

Explanation:

R1: 1 Ω

R2 : 6 Ω

R3 : 3 Ω

let total resistance of parallel connection = R₀

⇒ 1/R₀ = 1/R2+1/R3

⇒ 1/R₀= 1/6 + 1/3 Ω

⇒ 1/R₀= 1/2 Ω

⇒ R₀= 2 Ω

let total resistance of parallel and series connection = Rₐ

⇒ Rₐ = R1+R₀

⇒ Rₐ= 1 + 2 Ω

⇒ Rₐ = 3 Ω