a circuit contains two 1.5 volt batteries and a bulb with a resistance of 3 ohms calculate the current (PLEASE ITS DUE SO SOON))
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2
V=IR
1.5=3*I
I= 0.5 Ampere
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0
Answer:
1 Ampere.
Explanation:
Voltage supplied by 2 batteries
= 1.5 V + 1.5 V = 3 V
Next we know a bulb is also connected in the circuit with resistance 3 ohms.
let this be R1 = 3 ohms.
Assumption:
The wire offers no resistance
There is no heat loss.
Then, you can use Ohm's Law which relates current and voltage supplied in a circuit as:
V = I R
V = voltage supplied.
I = cutrent flowing in the circuit.
R = Resistance
We already have the values :
3 V = I × 3 ohms
=> 3 V / 3 ohms = I
=> 1 V / ohm = I
=> 1 Ampere = I
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