A circuit has a fuse of 5a what is the maximum no of 100w(220v) bulb that can be supply
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⭐⭐⭐ Hey mate!!⭐⭐⭐
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⚡❄️ Let x number of such bulbs can be used.
Power of one bulb =100 watt
Power of x bulbs (p)= 100 × x watts
Potential difference (V) =220 volts
I=5 A
❄️ We know that P= V I
100x =220 ×5
x= 220 ×5/100
X = 11
Hence,
Number of bulbs connected = 11
Hope it will help you....⚡✌️
#phoenix⭐
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