A circuit has a line of 5A How many lamps of rating 40W and 220V can simultaneously glow on this line safely?
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Answer:
By using formula:
H=I(square)×R×T and
P=V(square)/R
Explanation:
h=40, I = 220v, R= ?
H=I(square)×R×T
40=220×220÷R
R=220×200÷40
R=1210 ohms
maximum number of resistance tube connected
r =V/I
r = 44 ohms
net resistance
r =R/n
n= 1210/44
n= 27.5
hence approximately we can connect 27 lamps safely
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