Question

A circuit has inductance of 2h. If the circuit current changes at the rate of 10a/second, then self induced emf is

Answer 1

When the current in a coil is changing an e.m.f will be induced in a nearby circuit due to some of the magnetic flux  produced by the first circuit linking the second.This phenomenon is the mutual induction.

the  important thing is that the induce e.m.f  will last only by the the current in 1st circuit changes

M=E di/dt

    hence,E = -Mdi/dt,in which the :

                     E =emf

                      M = mutual inductance.

therefore E =-2*(0-10)/0.1= 200V

Answer 2

Answer:

The required self-induced emf is 20V

Explanation:

Due to a portion of the magnetic flux generated by the first circuit connecting the second, an e.m.f. will be induced in an adjacent circuit when the current in a coil changes. Mutual induction is the phenomenon at hand.

With the use of electricity and other types of artificial and natural illumination, invisible energy fields known as electric and magnetic fields (EMFs) and radiation are created.

The crucial factor is that the induced e.m.f. will only last as long as the first circuit's current changes.

The self-induced EMF is given as

E = Ldi/dt

$=2$ × $10$

$=20 V$

Therefore, self-induced emf is $20V$.

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