A circuit has resistance of 12 ohm and impedeance of 15ohm the power factor of circuit will be
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Impedance ( Z ) is the effective resistance to current flow.
Z = ZR + ZL + ZC
Here: R = 12 Ohm, Z = 15 Ohm
The power factor ( PF ) of the circuit is equal to the cosine of power phase angle ( Ф ).
PF = cos ( Ф ) = R / Z
PF = 12 Ohm / 15 Ohm
PF = 0.8
Answer: The power factor of the circuit will be 0.8.
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