a circuit is made of 0.4 ohm a 150 ohm bulb and a 120 ohm rheostart connected in series.determine the total resistance of the circuit.
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Resistance of wire = 0 . 4ohms
Resistance of bulb = 150 ohms
Resistance of rheostat = 120 ohms
CIRCUIT IN SERIES
Total resistance ,R = R1 + R2 + R3
R = 0. 4 + 150 +120 = 270 . 4 ohms
Resistance of wire = 0 . 4ohms
Resistance of bulb = 150 ohms
Resistance of rheostat = 120 ohms
CIRCUIT IN SERIES
Total resistance ,R = R1 + R2 + R3
R = 0. 4 + 150 +120 = 270 . 4 ohms
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