a circuit is made of 0.4 ohm a 150 ohm bulb and a 120 ohm rheostart connected in series.determine the total resistance of the circuit.
Answers
Answered by
1
GIVEN
Resistance of wire = 0 . 4ohms
Resistance of bulb = 150 ohms
Resistance of rheostat = 120 ohms
CIRCUIT IN SERIES
Total resistance ,R = R1 + R2 + R3
R = 0. 4 + 150 +120 = 270 . 4 ohms
Resistance of wire = 0 . 4ohms
Resistance of bulb = 150 ohms
Resistance of rheostat = 120 ohms
CIRCUIT IN SERIES
Total resistance ,R = R1 + R2 + R3
R = 0. 4 + 150 +120 = 270 . 4 ohms
Answered by
0
Answer:
Refer to the attachment
Attachments:
Similar questions
Science,
8 months ago
Physics,
1 year ago
Social Sciences,
1 year ago
Science,
1 year ago
Math,
1 year ago