a circuit is made of 0.4 ohm wire, a 150 ohm bulb ,a 120 ohm rheostat connected in series. determine the total resistance of the resistance of the circuit
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As all are connected in series, it is easy to calculate the total resistance of the entire circuit.
Let R1 = 0.4 ohm, R2 = 150 ohm and R3 = 120 ohm.
Therefore,
Total Resistance (R) = R1 + R2 + R3 = (0.4 + 150 + 120) ohm =270.4 ohm
Let R1 = 0.4 ohm, R2 = 150 ohm and R3 = 120 ohm.
Therefore,
Total Resistance (R) = R1 + R2 + R3 = (0.4 + 150 + 120) ohm =270.4 ohm
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