A circuit is shown in the diagram given below -
a) find the value of R.
b)find the reading of the ammeter.
c) find the potential difference across the terminals of the battery.
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Question

A circuit is shown in the diagram given below:-
(a) Find the value of RR.
(b) Find the reading of the ammeter.
(c) Find the potential difference across the terminals of the battery.


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Solution

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In the given circuit , all the resistors are connected in the series combination. therefore, current flowing through them is same.(Let say I)
∙ Voltage across 6 Ω resistor is 12V
We know,
Electric current,I=resistance(R)voltage(V)
Or, I=612=2A
∙ Voltage across unknown Resistor R resistor is 6V
The current flowing through R is also 2A.
Part(A) Finding value of R
We know,
According to Ohm law, V=IR
Or Resistance ,R=IV=26=3Ω
here,
Requivalent=R1+R2
Requivalent=3+6=9Ω
Hence Equivalent resistance is =9Ω
Part(B) Calculate Reading of the ammeter.
Ammeter is a device which is used to measure Electric current in the circuit,
Hence reading =2A
Part(C) In series combination, Potential of the battery is always equals to the, sum of the potential difference across all the resistors which are connected in series combination.
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