Question

A circular coil having N turns and radius r carries a current. It is held in the XZ plane in a magnetic field Bî
. The torque on the coil due to the magnetic field is:
(A) Br²1/πN
(B) zero
(C)
Bπr²1/N
(D) Bπr²IN

Answer 1

Answer:

Correct Option is :

(D ). Torque = NIπr²B

Explanation :

Torque = NIAB sin ¢

Here, ¢ = 90°

Torque = NIπr²B