A circular coil lies in the plan has 5 turns each of 4cm radius, 4 ampere current flows through it, which is clockwise to us. Find the magnitude and direction of the magnetic field at the centre of the coil.
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Answered by
7
hey mate!
Magnetic field at x=0(at centre) due to circular current carrying wire is.
B° =mu nod N I / 2R
N = number of turns
R= redius
B° = 4 π ×10 ^-7 ×5 × 4 /2 ×2×10-^2
B°. = 20π ×10^-5T
#phoenix..
Answered by
3
hey mate!
Magnetic field at x=0(at centre) due to circular current carrying wire is.
B° =mu nod N I / 2R
N = number of turns
R= redius
B° = 4 π ×10 ^-7 ×5 × 4 /2 ×2×10-^2
B°. = 20π ×10^-5T
#phoenix..
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