Question

solve for x and y 2/root x + 3/root y =2 and 4/root x - 9/root y = -1

Answer 1

This is the answer
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Answer 2

Answer:

$x=4$ and $y=9$

Step-by-step explanation:

The given equation is:

$\frac{2}{\sqrt{x}}+\frac{3}{\sqrt{y}}=2$ and $\frac{4}{\sqrt{x}}-\frac{9}{\sqrt{y}}=-1$.

Now, multiply first equation by 3 and then add the second equation, we get

⇒$6\sqrt{y}+9\sqrt{x}+4\sqrt{y}-9\sqrt{x}=6\sqrt{x}\sqrt{y}-\sqrt{x}\sqrt{y}$

⇒$10\sqrt{y}=5\sqrt{x}\sqrt{y}$

⇒$\sqrt{x}=2$

Squaring on both sides, we get

$x=4$

Now, substituting the value of x=4 in the first equation, we get

$2\sqrt{y}+6=4\sqrt{y}$

$\sqrt{y}=3$

Squaring on both sides, we get

$y=9$

Thus, $x=4$ and $y=9$