Question

A circular coil of 20 turns each of radius 10cm and carrying a current of 5A is placed in a uniform
magnetic field of induction 0.10T normal to the plane of the coil. What is torque acting on the coil?
a) 0.314 Nm
b) Zero
c) 31.4 Nm
d) 3.14 Nm​

Answer 1

Answer:

a) 0.314

Explanation:

torque =nIAB

20×5×0.1×3.14×(10×10^-2)^2

=0.314