Question

In the magnetic meridian of a certain place, the horizontal component of the earth's magnetic field is 0.26 units and the angle of dip is 60'. What is the magnetic field of the earth at this location ?

Answer 1

Always make a diagram while doing these kind of sums. Good Luck...

Answer 2

Answer:

Earth's Magnetic Field H = 0.26

Angle of dip δ = 60°

Since the horizontal component of the magnetic field is the cosine function of H, which implies that;

H = R cos δ

R = H/cos δ

Substituting the values in the upper relation,

R = 0.26/ cos 60°

As we know that cos 60° = 1/2;

R = 0.26/(1/2) = 2*0.26 = 0.52 units

R = 0.52 units