Question

A circular coil of radius 10cm,500 turns and resistance 2Ω is placed with its plane perpendicular to the horizontal component of the earth’s magnetic field. It is rotated about its vertical diameter through 180∘ in 0.25s. Estimate the magnitudes of the emf and current induced in the coil. Horizontal component of the earth’s magnetic field at the place is 3.0×10–5 T.

Answer 1

Answer:

induced EMF in the coil is $EMF = 3.77 \times 10^{-3} V$

current in the coil is $i = 1.88 \times 10^{-3} A$

Explanation:

As per Faraday's Law of electromagnetic induction we know that rate of change in magnetic flux is induced EMF of the coil

So we will have

$EMF = \frac{\Delta \phi}{\Delta t}$

$EMF = \frac{2NBA}{\Delta t}$

$EMF = \frac{2(500)(3\times 10^{-5})\pi(0.10^2)}{0.25}$

$EMF = 3.77 \times 10^{-3} V$

Now the induced current is given as

$i = \frac{EMF}{R}$

$i = \frac{3.77 \times 10^{-3}}{2}$

$i = 1.88 \times 10^{-3} A$

#Learn

Topic : Faraday's law

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