Physics, asked by tumtere764, 1 year ago

27.
A projectile A is projected from ground. An
observer B running on ground with uniform
velocity of magnitude 'v'observes A to move
along a straight line. The time of flight of A as
measured by B is T. Then the range R of projectile
on ground is :-
(1) R = vT
(2) R< vt
(3) R > vt
(4) information insufficient​

Answers

Answered by tarun81514525
2

Explanation:

we know that

  1. R=2vsquare sinø cosø/g
  2. Time of flight=2usinø/g

then,

R=v(2vsinø)cosø/g

R=vcosøT

where t is equal to the time of flight

given that projectile is in straight line then ø =90 degrees

so,R=vcos(90)T. cos (90)=0

R=0

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