A circular coil of radius 4cm and 20 turns carries 3 ampere current.find the magnetic moment of coil
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Answer:
Given that radius(r)=4cm=0.04m
Number of turns, n=20
Current in the coil, i=3A
We know that, area of a circular coil, A=πr2
Therefore area of our current carrying coil, A=π×(0.04)2=0.00502m2≃0.0050m2(approximating)
We also know that magnetic dipole moment, M=niA=20×3×0.0050=0.3A−m2
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