Question

A car is moving in a straight line from rest and travels a distance 20 m in 4 s with constant acceleration Calculate this acceleration​

Answer 1

Answer:

Acceleration is 2.5 m/s².

Explanation:

To find : Acceleration of car.

We have,

• Initial velocity, u is 0 m/s.
• Distance, s is 20 m.
• Time, t is 4 s.

We know,

Second equation of motion :

• s = ut + 1/2 at²

[Where, a is acceleration]

Now, Put s, u and t in formula :

$\longrightarrow$ 20 = 0 × 4 + 1/2 × a × (4)²

$\longrightarrow$ 20 = 0 + 1/2 × a × 16

$\longrightarrow$ 20 = 16a/2

$\longrightarrow$ 20 × 2 = 16a

$\longrightarrow$ 40 = 16a

$\longrightarrow$ 40/16 = a

$\longrightarrow$ a = 2.5

Thus,

Acceleration of car is 2.5 m/s².

Answer 2

Given :-

A  car is moving in a straight line from rest and travels a distance 20 m in 4 s with constant acceleration

To Find :-

Acceleration

Solution :-

By using the formula

s = ut + 1/2 at²

Where

s = distance

u = initial velocity

a = acceleration

20 = (0)(4) + 1/2 × a × (4)²

20 = 0 + 1/2 × a × 16

20 = 8a

20/8 = a

5/2 = a

2.5 = a

the acceleration is 2.5 m/s²