Question

11 oranges are bought for 10 and 10 oranges are sold for 11. Find the gain or loss per cent ​

Answer 1

Answer:

21% gain

Step-by-step explanation:

C.P pf 11 oranges = Rs 10

∴ C.P pf 1 orange = Rs (  

11

10

​

)

Also, S.P of 10 oranges = Rs 11

∴ S.P of 1 orange = Rs  (  

10

11

​

)

Now, profit = S.P .- C.P.=  

10

11

​

−  

11

10

​

=Rs  

110

21

​

 

∴ Profit % =  

11

10

​

 

110

21

​

 

​

×100=21%

Answer 2

Answer:

Gain % = 21%

Step-by-step explanation:

I believe your Question was,

"11 oranges are bought for ₹10 and 10 oranges are sold for ₹11. Find the gain or loss per cent"

Now,

We see that 11 oranges are bought for ₹10

So, we can say that,

Cost Price (C.P) of 11 oranges = ₹10

C.P of 1 orange = ₹(10/11)

Similarly, we see that 10 oranges we sold for 11

So,

Selling Price (S.P) of 10 oranges = ₹11

S.P of 1 orange = ₹(11/10)

Here, if we observe that,

₹(11/10) > ₹(10/11)

S.P > C.P

So, it is a Profit.

We know that,

Profit = S.P - C.P

P = ₹(11/10) - ₹(10/11)

To subtract they must be like fraction, and to be like fraction they must have equal denominators.

So, let's take LCM of the denominators,

LCM (11, 10) = 110

So,

(11/10) × (11/11) = (121/110) (S.P)

And,

(10/11) × (10/10) = (100/110) (C.P)

Then,

P = (121/110) - (100/110)

P = (121 - 100)/110

P = ₹(21/110)

Now,

Profit % = (Profit/C.P) × 100

So,

P% = [(21/110) ÷ (100/110)] × 100

P% = [(21/110) × (110/100)] × 100

P% = (21/100) × 100

P% = 21 %

Hence,

Gain % = 21%

Hope it helped you and believing you understood it...All the best