Question

A hammer of mass '0.01sec' , moving at '20m//s' , strikes a nail. The nail stops the hammer in a very short time of '500" "g' . What is the magnitude of the force due to nail on the hammer?​

Answer 1

Answer:

$\dag \sf \pink{Here \: is \: your \: Answer}$

m = 500g = 0.5 kg

v = 0 m/s

u = 50 m/s

t = 0.01 s

F = m(v-u) / t

F = 0.5 (50-0) / 0.01

F = 0.5 x 50 x 100 / 1

F = 2500 N

Force of nail = 2500 N

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